Java 范型中的super和extends的区别

其实一句话就是:

super最好用来作为输出参数,extends最好用来作为输入参数;

看看下面的例子:

private class A {
    //
}

private class B extends A {
    //
}

private class C extends B {
    //
}

public void test() {
    List<? super B> test = new ArrayList();
    test = new ArrayList<A>();
    test = new ArrayList<B>();
    test = new ArrayList<C>(); //不能接受比B还小的类

    A a = test.get(0);//不能get
    B b = test.get(0);//不能get
    C c = test.get(0);//不能get

    test.add(new A());//但是不能add比B大的类
    test.add(new B());
    test.add(new C());

    List<? extends B> test1 = new ArrayList();
    test1 = new ArrayList<A>();//不能接受比B大的类
    test1 = new ArrayList<B>();
    test1 = new ArrayList<C>();

    A a1 = test1.get(0);
    B b1 = test1.get(0);
    C c1 = test1.get(0);//但是不能get比B小的类

    test1.add(new A());//不能add
    test1.add(new B());//不能add
    test1.add(new C());//不能add

}

下面是在Eclipse中的编译错误截图:

具体的原因可以参见:

http://stackoverflow.com/questions/4343202/difference-between-super-t-and-
extends-t-in-java

http://docs.oracle.com/javase/tutorial/java/generics/capture.html